How do I calculate CC's ? - Yamaha ATV Forum
 
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post #1 of 14 Old 12-05-2001, 11:04 PM Thread Starter
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What is the formula for figuring out my displacement? My motor is bored out .020 over in case anyone already knows.
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post #2 of 14 Old 12-06-2001, 03:15 AM
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You gained maybe 3-4 cc's.


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post #3 of 14 Old 12-06-2001, 05:41 AM
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radius squared, multiply by pi, and then multiply that by your stroke, you can then multiply that number by number of cylinders. Thats it!
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post #4 of 14 Old 12-06-2001, 08:54 PM
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Quote:
On 2001-12-05 22:04, ultim8warrior wrote:
What is the formula for figuring out my displacement? My motor is bored out .020 over in case anyone already knows.
B x B x 0.7854 x S x N

B = BORE cm
S = STROKE cm
N = NUMBER OF CYLINDERS

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post #5 of 14 Old 12-07-2001, 01:47 AM
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cc's stands for cubic centimeters, couldnt you just fill it with water then peasure how much water? I dont think its a great idea to fill you engine with water thoe, maby use gas.

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post #6 of 14 Old 12-07-2001, 02:12 AM
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hmm, interesting formula, but its unique, thats why I use logic, and it always works, thats why I say:
- *pi(r)^2* <-formula for area of a circle
times stroke, will give you area of the cylinder,
times number of cylinders of course.
Its easy to remember, so you never have to look it up! Just remember the area of a circle and your fine!
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post #7 of 14 Old 12-07-2001, 05:22 PM
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Quote:
- *pi(r)^2* <-formula for area of a circle
It's the same formula.

r = 1/2 bore
pi = 4 x .7854

We know the bore and stroke, so we don't need to measure the radius. Remove the logic and it's Engine cc's for Dummies. ;)

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post #8 of 14 Old 12-07-2001, 11:40 PM Thread Starter
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I tried badercarma's suggestion and I almost got smashed by my own 4-wheeler. HOLY CRAP that thing was hard to flip over to get the water out back out.

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post #9 of 14 Old 12-08-2001, 01:31 AM
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They actually do that suggestion in some sancioning bodies of drag racing to confirm that you have the displacement you say you do. You dont turn the quad over of course, you just leave the plug out and crank it over... I'm not sure what they use to fill it with, though.
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post #10 of 14 Old 12-08-2001, 02:00 AM
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take the height of your shatf and divide it by 2.21 then add the numbers of tries your scooter has and then thats it......make sure that you change your bumber oil and lube your hammerrod rod 10w40!
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post #11 of 14 Old 02-11-2002, 05:05 PM
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another "less scientific way" is to take the number of lugnuts on your bike divided by the number of links on your chain. mltipy this by the length of your swingarm and then add to the combined number of inches of travel your front shocks offer. subtract this number from your date of birth and add your current age. you now have your answer. wasn't that easy??!! :)20 :)20 :)20 :)20 :)20 :)20 thanks for the info there. obviously, yours is more informative than mine.

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post #12 of 14 Old 02-11-2002, 07:02 PM
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pi * radius^2 * bore

All the measurements must be in CM if you want CCs

a raptor is 100mm bore and 84mm stroke
so change it to cm:10cm bore and 8.4 cm stroke
radius = 1/2 the bore, or 5 cm

3.1415 * 5^2 * 8.4=
3.1415 * 25 * 8.4 = 659.715cc

Now .020" over = 0.5080mm
so the equation is:
100.508mm bore
84mm stroke
convert to cm
10.0508cm bore
8.4cm stroke
plug into the above formula
3.1415 * 5.0254^2 * 8.4=
3.1415 * 25.255 * 8.4 = 666.444

So on a raptor the displacement change is 666.444 - 659.715 = 6.729ccs larger

that's just a little over 1% larger than stock..

damn.. and I just noticed you have a warrior.. not raptor

83 bore x 64.5mm stroke
same numbers apply
348.97 cc stock
353.26 bored .020 over

difference of 4.29ccs








<font size=-1>[ This Message was edited by: RaptorBrad2 on 2002-02-11 18:05 ]</font>
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post #13 of 14 Old 02-11-2002, 07:12 PM
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post #14 of 14 Old 02-12-2002, 11:40 AM
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pi*(r*r)*stroke divide by 1000, r is the radius of your piston

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